【LeetCode】54. 螺旋矩阵

54. 螺旋矩阵

思路

  1. 偏移量技巧
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输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:[1,2,3,6,9,8,7,4,5]

matrix

拓展

  1. 【每日一题3】AcWing 756. 蛇形矩阵
  2. 59. 螺旋矩阵 II

代码

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class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
int m=matrix.size();
int n=matrix[0].size();
vector<int> ans;
int f[15][15]={0};
int dx[] = {-1, 0, 1, 0}, dy[] = {0, 1, 0, -1};
int x = 0, y = 0, d = 1;
for (int i = 0; i < n * m; i ++ )
{
ans.push_back(matrix[x][y]);
f[x][y]=1;
int a = x + dx[d], b = y + dy[d];
if (a < 0 || a >= m || b < 0 || b >= n || f[a][b])
{
d = (d + 1) % 4;
a = x + dx[d], b = y + dy[d];
}
x = a, y = b;
}
return ans;
}
};