【每日一题26】AcWing 1101. 献给阿尔吉侬的花束

Day26 AcWing 1101. 献给阿尔吉侬的花束

思路

  1. bfs求最短路径
    • 队列实现bfs

代码

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#include<bits/stdc++.h>
using namespace std;

#define x first
#define y second

const int N=200;
typedef pair<int, int> PII;

int n;
int r,c;

char maze[N][N];
int dist[N][N];

int bfs(PII start)
{
queue<PII> q;
q.push(start);
memset(dist,-1,sizeof(dist));
dist[start.x][start.y]=0;

int dx[] = {-1, 0, 1, 0}, dy[] = {0, 1, 0, -1};
while(q.size())
{
auto t=q.front();
q.pop();
res++;
for(int i=0;i<4;i++)
{
int x=t.x+dx[i],y=t.y+dy[i];
if (x >= 0 && x < r && y >= 0 && y < c && maze[x][y] != '#' && dist[x][y] == -1)
{
dist[x][y] = dist[t.x][t.y] + 1;
if (maze[x][y] == 'E')
return dist[x][y];
q.push({x, y});
}
}


}
return -1;
}
int main()
{
cin>>n;
while(n)
{
cin>>r>>c;
int x,y;
PII start;
for(int i=0;i<r;i++)
for(int j=0;j<c;j++)
{
cin>>maze[i][j];
if(maze[i][j]=='S') start={i,j};
}
int ans=bfs(start);
if(ans!=-1)
cout<<ans<<endl;
else
cout<<"oop!"<<endl;
n--;
}

}